Question

calculate the mole fraction of ethanol in a solution made by dissolving 9.2g ethanol in 18g water

Answer 1

Explanation:

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Answer 2

Concept:

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Given:

The mass of ethanol = 9.2 g

The mass of water = 18 g

Find:

Find the mole fraction of each component in 9.2 g ethanol and 18 g water.​

Solution:

The number of moles (n) of a component can be calculated as:

                     n = Mass / Molar mass

Molar mass of water and ethanol are 18 g/mol and 46 g/mol respectively.

The number of moles of ethanol = 9.2 g / 46 g/mol = 0.2moles

The number of moles of water = 18 g / 18 g/mol = 1 moles

The mole fraction of ethanol can be calculated as follows below.

Mole fraction of ethanol =  Number of moles of ethanol / ( Number of moles of ethanol + Number of moles of water)

= 0.2 moles / (0.2 + 1) moles

= 0.2 / 1.2

= 0.167

Mole fraction of water = Number of moles of water / ( number of moles of ethanol + number of moles of water)

= 1 moles / (0.2 + 1) moles

= 6 / 1.2

= 5

Hence, the mole fraction of each component in 9.2 g ethanol and 18 g water are 0.167 and 5 respectively.

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