Question

calculate the mole fraction of ethylene glycol and water in a solution containing 20%of c2H6O2 by mass​

Answer 1

Answer:

0.0677

Explanation:

% of ethylene glycol (mass) = 20%

let , total mass = x g

ethylene glycol= 0.2x  g = $\frac{0.2x}{62}$  mole =0.003226x mole

water = 0.8x   g = $\frac{0.8x}{18}$ mole = 0.044444444 mole

mole fraction of ethylene glycol = $\frac{0.003226x}{0.003226x + 0.044444444x}$ = 0.0677