Question

Calculate the mole fraction of ethylene glycol in a solution containing 20 percent of c2h6o2 by mass

Answer 1

Answer:calculate the mole fraction ethylene glycol {C2H6O2} and water in a solution containing 20% of C2H6O2 by mass. Answer: 20% of C2H6O2 by mass is present. That means solution has 20 g of ethylene glycol and 80 g of water

Explanation:

Answer 2

Hey Dear,

I assume you're talking about aqueous solution here.

◆ Answer -

Mole fraction of ethylene glycol = 0.06768

◆ Explanation -

Consider C2H6O2 dissolved in water.

Lets say, 100 g of solution contains 20 g of C2H6O2 and 80 g of water.

Moles of ethylene glycol is calculated as -

n1 = 20 / 62

n1 = 0.3226 mol

Moles of water is calculated as -

n2 = 80 / 18

n2 = 4.444 mol

Mole fraction of ethylene glycol in solution is -

X = n1 / (n1 + n2)

X = 0.3226 / (0.3226 + 4.444)

X = 0.06768

Hence, mole fraction of ethylene glycol in solution is 0.06768.

Hope this helped you.