Question

calculate the mole fraction of ethylene glycol in an aqueous solution containing 10% ethylene glycol by mass​

Answer 1

Explanation:

Mole fraction of ethylene glycol = No of moles of ethylene glocal/ Total number of moles.

= 0.32/(0.32 + 4.44)

= 0.068 .

1. Mole fraction of water = 1-0.068 = 0.932.

Answer 2

Answer:

Hello !✌

As given in the question, a solution of ethylene glycol and water contains 10% of ethylene glycol by mass.

That is, in 100g of solution - 10g of ethylene glycol.

Molar mass of ethylene glycol - (12*2 + 1*6 + 16*2) = 62g/mol.

so, in 10g we have 10/62 = 0.16 mol.

remaining 90g contains water. Number of moles of water = 90/18 = 5 mol

Mole fraction of ethylene glycol = No of moles of ethylene glocal/ Total number of moles.

= 0.16/(0.16 + 5)

= 0.03.

Mole fraction of water = 1-0.03 = 0.97.

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