Question

Calculate the mole fraction of glycerol (C3H8O3)Solution in 25% by weight of glycerol

Answer 1

The question is incomplete, here is the complete question:

Calculate the mole fraction of aqueous glycerol (C₃H₈O₃) solution in 25% by weight of glycerol

The mole fraction of glycerol is 0.0613

Explanation:

We are given:

25 % glycerol solution

This means that 25 grams of glycerol is present in 100 grams of solution

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

• For glycerol:

Given mass of glycerol = 25 g

Molar mass of glycerol = 92 g/mol

Putting values in equation 1, we get:

$\text{Moles of glycerol}=\frac{25g}{92g/mol}=0.272mol$

• For water:

Given mass of water = [100 - 25] g = 75 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{75g}{18g/mol}=4.167mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

Mole fraction of glycerol, $\chi_{glycerol}=\frac{0.272}{0.272+4.167}=0.0613$

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