calculate the mole fraction of glycerol solution in 25% by weight of glycerol
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25% by mass means 25g of glycerol in 100g water.
ie; given mass of glycerol = 25g
molar mass of glycerol = 92g
no: of moles of glycerol = given mass/
moleclr mass
= 25÷92=0.27
given mass of solvent =100-25=75g
molecular mass of water = 18g
therefore,no of moles = 75÷18=4.16
molefraction = 0.27÷(0.27+4.16)
=0.06
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Answer:
Given that :
w = mass of glycerol = 25 gm
m = molecular mass of glycerol = 92 gm
W = mass of solvent which in our case is water = 100 -25 = 75 gm
M = molecular mass of solvent = 18 gm
we know that -
mole fraction = w÷m/w÷m+W÷M
=25÷92/25÷92+75÷18
mole fraction = 0.06
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