Question

CAlculate the mole fraction of H2SO4
in a solution conatining 98% H2SO4
by mass.

Answer 1

Answer:

90/: of h2 so4 will contaiass

Answer 2

98% H$_{2}$SO$_{4}$ by mass means 98 gm of H$_{2}$SO$_{4}$ present 100gm of solution

$\sf\pink{Mass~of~solute}$ (H$_{2}$SO$_{4}$) = 98 gm

$\sf\green{No.~ of ~moles~ of}$ H$_{2}$SO$_{4}$ , n$_{A}$ = $\sf\frac{ 98 }{ 98 }$ = 1

$\sf\red{Mass ~of}$ H$_{2}$O = 100 - 98 = 2 gm

$\sf\blue{No. ~of ~moles~ of}$ H$_{2}$O , n$_{B}$ = $\sf\frac{ 2 }{ 18 }$ = $\sf\frac{ 1 }{ 9 }$

$\sf\purple{Mole~ of~ fraction~ of}$ H$_{2}$SO$_{4}$ =

$\frac{1}{1 \: + \: \frac{1}{9}} \: = \: \frac{9}{10} \: = \: 0.9$