Question

calculate the mole fraction of H2SO4 in a solution containing 98% [w/w]H2SO4 by mass. ​

Answer 1

Answer:

0.9

Explanation:

98%(w/w) H2SO4 by mass means 100gof solution contains 98g of H2SO4 as solute.

wt. of solute = 98g

no.of mol of solute = 98g/98g/mol

= 1mol

no.of mol of solvent = 2g/18g/mol

= 0.11mol

mole fraction of H2SO4 = mol of H2SO4/total no.of moles

= 1/1.11 = 0.9

Answer 2

Concept:

The mole fraction is calculated by dividing the number of moles of a certain component in a solution by the total number of moles in the solution.

The mole fraction is not affected by temperature.

It is not essential to know the density of the phase to determine the mole fraction.

The mole fraction of an ideal gas mixture is defined as the ratio of partial pressure to total pressure of the mixture.

Find:

Mole fraction of the compound.

Solution:

$98\%$(w/w) $H_2SO_4$ by mass means $100gm$ of solution contains $98gm$  of  $H_2SO_4$ as solute.

wt. of solute = $98gm$

number of mol of solute = $\frac{98gm}{98gm/mol}$

$=1mol$

number of mol of solvent = $\frac{2gm}{18gm/mol}$

$0.11mol$

mole fraction of $H_2SO_4$= mol of $H_2SO_4$/total no.of moles

$=\frac{1}{0.11} \\=0.9$

Hence, the mole fraction of $H_2SO_4$ is $0.9$.

#SPJ3