calculate the mole fraction of H2So4 in solution containing 98% H2So4 by mass
Answers
Answered by
45
Hi frnd.....
Density = 2.08 g/cc (assuming)
Weight of 1 litre of solution = 2.08 *1000 = 2080g
gram molecular weight of H2SO4 = 98g
Moles of H2SO4 = (2080-1000)/98 = 11.02 moles( 1 litre = 1000g and density of water=1)
moles of water = 1000/18 = 55.56
Mole fraction = 11.02/11.02+55.56 = 0.166.
Hope this may help u.....
Density = 2.08 g/cc (assuming)
Weight of 1 litre of solution = 2.08 *1000 = 2080g
gram molecular weight of H2SO4 = 98g
Moles of H2SO4 = (2080-1000)/98 = 11.02 moles( 1 litre = 1000g and density of water=1)
moles of water = 1000/18 = 55.56
Mole fraction = 11.02/11.02+55.56 = 0.166.
Hope this may help u.....
Answered by
27
Answer:0.909 is the answer
Explanation: I gave it in the below picture in detail
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