calculate the mole fraction of HCL and H2O in solution of hydrochloric acid in water containing 30% of HCL by weight
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Answer:-
• Mole fraction of HCl = 0.17
• Mole fraction of H₂O = 0.83
Explanation:-
In this solution, HCl [Hydrochloric acid] is solute and H₂O [Water] is solvent.
Let the total mass of the solution
be 100g.
Then, mass of HCl is 30g,
and mass of H₂O :-
= 100-30
= 70g
Molar mass of HCl :-
= 1+35.5
= 36.5g/mol
Molar mass of H₂O :-
= 1×2+16
= 18g/mol
Number of moles in 30g HCl :-
= Given Mass/Molar mass
= 30/36.5
= 0.82 mole
Number of moles in 70g H₂O :-
= Given Mass/Molar mass
= 70/18
= 3.89 mole
Mole fraction of solute [HCl] :-
= Mole of solute/Total mole in solution
= 0.82/[0.82+3.89]
= 0.82/4.71
= 0.17
Mole fraction of solvent [H₂O] :-
= Mole of solvent/Total mole in solution
= 3.89/[0.82+3.89]
= 3.89/4.71
= 0.83
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