Question

Calculate the mole fraction of HCl and Water in a solution of HCl acid in water containing 30% HCl by weight.​

Answer 1

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Answer 2

$\huge\mathfrak{Answer}$

$\huge\sf{solution:}$

Let the weight of the solution be 100 g

Then,

Weight of HCl = [tex] \frac{30}{100}×100=1 [/tex]

Weight of Water in solution= ( 100-30 ) = 70 g

Now,

$no.of \: moles \: of \: hcl = \frac{given \: wt \: }{formula \: wt \: }$

$no \: of \: moles \: of \: hcl = \frac{30}{36.5}$

$no \: of \: moles \: of \: hcl = 0.98$

Similarly no. of moles of water =

$= \frac{70}{18}$

$= 3.8moles$

$now \: mole \: fraction \: = \frac{no \: of \: moles \: }{weight \: of \: solvent}$

$mole \: fraction \: of \: hcl = \frac{0.98}{70 }$

$mole \: frac \: of \: hcl \: = 0.0 14$

similarly,

$mole \: frac \: of \: water = \frac{3.8}{70} = 0.054$