calculate the mole fraction of NaOH in a solution containing 20g of NaOH per 360g of water (Na=23,O=16 h=1.008
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NaOH solution is prepared in water.
Molar mass of NaOH=40 g
Mass of NaOH=10 g
Molar mass of water = 18 g
Given mass of water = 90 g
Number of moles of NaOH=
40
10
=0.25 moles
Number of moles of H
2
O=
18
90
=5 moles
Mole fraction of NaOH=
0.25+5
0.25
=0.047
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