Calculate the mole fraction of O2 in a saturated solution of oxygen in water at 25 C . The partial pressure of oxygen above solution is 0.21 atm. Given Kh of o2 is 2.3×10^5 atm^-1
Answers
Given info : The partial pressure of oxygen above solution is 0.21 atm. Given KH of o2 is 2.3×10^5 atm
To find : The mole fraction of O2 in a saturated solution of oxygen in water at 25°C.
solution : partial pressure of oxygen above solution, P = 0.21 atm
Henry's constant, KH = 2.3 × 10⁵ atm
according to Henry's law,
P = KH × x
⇒x = P/KH
x = 0.21 atm/2.3 × 10⁵ atm
= 0.091 × 10¯⁵ = 9.1 × 10^-7
Therefore the mole fraction of oxygen in a saturated solution of oxygen in water is 9.1 × 10^-7.
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