Question

calculate the mole fraction of of ethyl alcohol and water in a solution in which 46g of ethyl alcohol and 90g of water​

Answer 1

$\red{ \ Answer :-}$

molecular mass of C2H6O (ethanol) = 46amu

molecular mass of H2O = 18amu

no. of moles = $\frac{given \ mass}{molecular \ mass}$

therefore, no. of moles of ethyl alcohol (ethanol) = 46/(molecular mass of C2H6O)

$\tt{\implies}$ $\cancel\frac{46}{4}$

$\tt{\implies}$1 moles

no.of moles of H2O=90/(molecular mass of H20)

$\tt{\implies}$ $\cancel\frac{90}{18}$

$\tt{\implies}$5 moles

total moles = moles of ethanol + moles of H2O

$\tt{\implies}$ 1+5=6 moles

mole fraction of sub.= moles of sub./total moles

mole fraction of ethanol= $\cancel\frac{1}{6}$

$\tt{\implies}$ 0.1666

Hope it's helps you :)