Question

calculate the mole fraction of sodium hydroxide in 10% w/w NaOH solution​

Answer 1

Answer:

h

Explanation:

calculate the mole fraction of sodium hydroxide in 10% w/w NaOH solution

NaOH? ∴ Molality =1040901000=1040×100090=2.778.

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Answer 2

The Moles Fraction Of Sodium Hydroxide in 10% w/w NaOH solution is 0.047

GIVEN:

Mass percentage of NaOH solution = 10%

TO FIND :

Mole fraction of SODIUM hydroxide.

SOLUTION:

10 % w/w of NaOH means that 10 grams of sodium hydroxide is present in 100 grams of solution.

Mass of NaOH = 10grams

Molar mass of NaOH = 23 + 16 + 1 = 40 grams

Number of moles of NaOH

= given mass /molar mass

= 10 /40.

= 0.25 moles.

Mass of water = 100 -10 = 90 grams.

Molar mass of water = 18 grams.

Number of moles of Water present in the solution= 90/18 = 5 moles

Mole fraction of Sodium hydroxide =

$\frac{Moles of NaOH }{moles \: sodium \: hydroxide \: and \: water}$

=

$\frac{0.25}{0.25 + 5}$

= 0.047

Hence, The Moles Fraction Of Sodium Hydroxide is 0.047

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