Question

calculate the mole fraction of solute and solvent in 20% of w by v of naoh aqueous solution if density given 1.25 g by mol plz give m full ans with explanation
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Answer 1

Answer:

20% W/W aqueous solution of NaOH

20g of NaOH in 100g of solution

Solution=solute+solvent

100=20+solvent

80g=solvent

20g of NaOH in 80g of water

n

NaOH

=

40

20

=

2

1

=0.5

n

H

2

O

=

18

80

=4.44

Mole fraction of NaOH=

n

NaOH

+n

H

2

O

n

NaOH

=

0.5+4.44

0.5

=

4.94

0.5

=0.101

Thus, Mole fraction of solute is 0.1