Question

Calculate the mole fraction of solute in 10% weight/volume of NaOH (aq) solution. Given density of the solution is 1.5g/ml.​

Answer 1

Explanation:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ 10\% \:( w/v) \: of \: NaOH(aq) \: solution \\ density(ρ) = 1.5 \: g/ml \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ mole \: fraction \: of \: solute( Χ_{NaOH} )= ? \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ 10\% \:( w/v) \: of \: NaOH(aq) \: solution \\ means: 10g \: NaOH \: in \: 100ml \: solution \\ \boxed{n_{NaOH }= \frac{10}{40} = 0.25 \: mol }\\ mass \: of \:solution = density \times volume \\ = 1.5 \times 1000 = 150 \: g \\ mass \: of \: solvent(H_2O) = mass \: of \: solution \: - mass \: of \:solute(NaOH) \\ = 150 - 10 = 140 \: g \\ \boxed{n_{H_2O} = \frac{140}{18} = 7.77 \: mol} \\ Χ_{NaOH} = \frac{n_{NaOH}}{n_{NaOH }+ n_{H_2O}} \\ = \frac{0.25}{0.25 + 7.77} \\ = \frac{0.25}{8.02} \\ \boxed{Χ_{NaOH} = 0.031 } \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$