Calculate the mole fraction of solute in an aqueous solution containing 23.4 gm NaCl in 90 gm of water?
Answers
Answer:
to find the the molarity an mole fraction of the solute in the aqueous solution containing 23.4g of NaCl in 90g water we use the following description
Explanation:
moles of solute = 23.4 / 58.5
= 0.4 weight of solvent (water)
= 0.09kg Molality (m)
= no. of moles of solute / Weight of solvent in kg.
= 0.4 / 0.09 = 4.4444 ~ 4.45
total no.of moles in a solution = moles of water + moles of solute
= 5 + 0.4 = 5.4
Mole fraction of solute = no. of moles of solute / total no. of moles in a solution
= 0.4 / 5.4 = 0.740
Answer:
The mole fraction formula for a solution with containing one or more solutes is: Mole fraction of each solute = Number of moles of that solute divided by the total number of moles of all solutes and the solvent