Calculate the mole fraction of solution containing 2.5g of ethanoic acid in 75g of benzene
Answers
Answered by
0
1.Mole fraction is defined as= Number of moles of solute/ Number of moles of solution.
Molecular mass of ethanoic acid=60
Molecular mass of benzene=78
Number of moles of ethanoic acid= 2.5/60=0.041
Number of moles of benzene= 75/78=0.96153
Mole fraction= 0.041/(0.041+0.96153)=0.040
2. Molality = Number of moles of solute/weight of the solvent (in kg)
= 0.041/0.075
=0.5466
Similar questions