Calculate the mole fraction of solution of solvent in 20 percent w/v percent of naoH (aq) solñ. given d solñ = 1.25g/ml
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Answer:
20% W/W aqueous solution of NaOH
20g of NaOH in 100g of solution
Solution=solute+solvent
100=20+solvent
80g=solvent
20g of NaOH in 80g of water
n
NaOH
=
40
20
=
2
1
=0.5
n
H
2
O
=
18
80
=4.44
Mole fraction of NaOH=
n
NaOH
+n
H
2
O
n
NaOH
=
0.5+4.44
0.5
=
4.94
0.5
=0.101
Thus, Mole fraction of solute is 0.1
Explanation:
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