Question

Calculate the mole fraction of solution of solvent in 20 percent w/v percent of naoH (aq) solñ. given d solñ = 1.25g/ml​

Answer 1

Answer:

20% W/W aqueous solution of NaOH

20g of NaOH in 100g of solution

Solution=solute+solvent

100=20+solvent

80g=solvent

20g of NaOH in 80g of water

n

NaOH

=

40

20

=

2

1

=0.5

n

H

2

O

=

18

80

=4.44

Mole fraction of NaOH=

n

NaOH

+n

H

2

O

n

NaOH

=

0.5+4.44

0.5

=

4.94

0.5

=0.101

Thus, Mole fraction of solute is 0.1

Explanation:

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