Question

calculate the mole fraction of the A and B mixture in which 6.022×10^23 molecules of A and 10.4×10^23 molecules of B are present​

Answer 1

Answer:

Moles of H

2

SO

4

= Molarity of H

2

SO

4

× Volume of solution (L)

=0.02×0.1

=2×10

−3

moles

No. of H

2

SO

4

molecules =2×10

−3

×6.022×10

23

=12.044×10

20

molecules

Therefore, the correct option is A.

Answered By

Explanation:

एच के मोल्स

2

इसलिए

4

= एच की Molarity

2

इसलिए

4

× समाधान की मात्रा (एल)

= 0.02 × 0.1

= 2 × 10

-3

मोल्स

एच की संख्या

2

इसलिए

4

अणु = २ × १०

-3

× 6.022 × 10

23

= 12.044 × 10

20

अणुओं

इसलिए, सही विकल्प ए है।

द्वारा उत्तर दिया गया

hariom Mishra following me

Answer 2

Answer:

Explanation:

No.of mol of A = 6.022×10^23/6.022×10^23 = 1 mol

No.of mol of B = 10.4×10^23/6.022×10^23 =1.727

mole fraction of A = 1/2.727 = 0.366

mole fraction of B = 1 - 0.366 = 0.634