Question

calculate the mole fraction of the solute in aquepus solution containing 3.0 gram of urea in 250 g of water. (molecular mean of urea = 60).???​

Answer 1

HERE IS YOUR ANSWER MATE ----

Mass of solute1000

MolalityMolecular mass of solute mass of solvent in gram310000.260250

Mole fraction of urea =Moles of urea3 / 600.003593250Total moles6018

Mole fraction of water = 1 – 0.00359.

HOPE IT HELPS YOU

Answer 2

Answer:

0.0036.

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