Calculate the mole fraction of the total ions in an aqueous solution
prepared by dissolving 0.400 moles of CaF2 in 850.0 g of water.
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Answer:
=1/126
Explanation:
Mole fraction =no.of mole of solute /no.of mole of Sol
Mole of CaF2 0.4
Mole of water =850/18(H20=2×1+8×2basicaly molar mass)
=50mol
Now
Solute is Caf2 and Sol has Caf2and water thus
=0.4/50+0.4=1/126
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