Question

Calculate the mole fraction of water in a mixture containing 9 g water 120 g of acetic acid and 115 g of ethanol

Answer 1

The mole fraction of 115 g of ethanol is :-
115/9= 12.7



Hope this helps you.....!

Answer 2

Concept Introduction:-

The mole is the volume of a system's material that includes one mole worth of elementary entities.

Given Information:-

We have been given that  water in a mixture containing $9$ g water $120$ g of acetic acid and $115$ g of ethanol

To Find:-

We have to find that the mole fraction of water in a mixture

Solution:-

According to the problem

Mole fraction of water$=$number of moles of water$/$total number of moles.

Number of moles of water$=$mass$/$molar mass

Molar mass of water $= 18$ gram$/$mol

Number of moles of water $= 9/18$

Number of moles of water $= 0.5$

Molar mass of acetic acid $= 60$ g$/$mol

Number of moles of acetic acid $= 60/120$

Number of moles of acetic acid $= 0.5$

Molar mass of ethyl alcohol $= 46$ g$/$mol

Number of moles of ethanol $= 115/46$

Number of moles of ethanol $= 2.5$

Mole fraction

$=\frac{0.5}{0.5+0.5+2.5}\\=\frac{0.5}{3.5}\\=0.14$

Final Answer:-

The correct answer is the mole fraction of water in a mixture is $0.14$.

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