Calculate the mole fraction of water in a solution containing 9.2 grams of ethyl alcohol in 18 grams of water
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Xa+Xb=1.here Xa is mole fraction of solute(c2h5oh),Xb is mole fraction of solvent. Xb=nb/na+nb
na=9.2/46=1/5,
nb=18/18=1
=1/1+1/5=5/6=0.83
na=9.2/46=1/5,
nb=18/18=1
=1/1+1/5=5/6=0.83
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