Question

Calculate the mole fractions in a solution that contains 20.0 g of common salt and 80 g water.

Answer 1

SOLUTION:
Mass of solute=20g
mass of solvent =80
mass of solution =80+20=100

concentration =
100
20
​
×100
=20%


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Answer 2

Answer:

    X₂ = 0.071

    X₁ = 0.928

Explanation:

common salt - NaCl

mole fraction of solute (X₂) = n₂ / n₁ + n₂

mole fraction of solute (X₁) = n₁ / n₁ + n₂

n₁ = no of moles of solvent = w₁ / M₁

n₁ = 80 / 18 = 4.45mol

n₂ = no of moles of solute = w₂ / M₂

n₂ = 20 / 58.5

n₂ = 0.341mol

X₂ = n₂ / n₁ + n₂

     = 0.341 / 0.341 + 4.45

     = 0.341 / 4.791

     = 0.071

X₁ = n₁ / n₁ + n₂

    = 4.45 / 4.45 + 0.341

     = 4.45 / 4.791

     = 0.928

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