Question

Calculate the mole fractions of each compound in each of the following solutions: a. 19.4 g of H2SO4 in 0.251 L of H2O (density of water is 1.00 g/mL)

Answer 1

given, 19.4g of H2SO4 in 0.251L of H2O.

(density of water is 1g/ml).

molecular mass of H2SO4 = 98g/mol

so, no of moles of H2SO4 = 19.4/98 = 0.198 mol

volume of water = 0.251L = 251 ml

density of water = 1g/ml

so, mass of water = 251 × 1 = 251g

molecular mass of water = 18g/mol

so, no of moles of water = 251/18 = 13.944 mol

now mole fraction of H2SO4 = no of moles of H2SO4/(no of moles of H2SO4 + no of moles of water)

= 0.198/(0.198 + 13.944)

= 0.015

and mole fraction of water = 1 - 0.015 = 0.985

Answer 2

Answer:

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