Question

calculate the mole percentage of CH3OH and H2O respectively in 60%(by mass) aqueous solution of CH3OH

Answer 1

Answer:% CH3OH by mass = 60 %

mass of CH3OH ÷ mass of solution = 60/100

Let, the mass of the solution be 100 gm

Therefore, mass of CH3OH = 60 gm

and mass of H20 = 40 gm

moles of CH3OH = 60/32

moles of H20 = 40/18

% mole of CH3OH =( moles of CH3OH ÷ total moles ) X 100 = [60/32 ÷ (60/32 + 40/18)] X 100

= 45.76%

% mole of H20 = 100 - 45.76 = 54.24%

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