calculate the mole percentage of ch3oh H and H2O respectively in 60% by mass aqua solution of ch3oh h
Answers
answer:
Given,
60% by mass solution of CH
3
OH. That means in 100gm solution
60gm CH
3
OH is dissolved in 40gm H
2
O
∴ Molar mass of CH
3
OH=32g/mol
Molar mass of H
2
O=18g/mol
⇒ No. of moles of CH
3
OH=
32g/mol
60gm
=1.875 mol ..........(1)
No. of moles of H
2
O=
18gm/mol
40gm
=2.222 mol ..........(2)
Total no. of moles=1.875+2.222=4.097 moles ..........(3)
⇒ Mole percentage=
Total no. of moles
Moles of compound
×100
Mole % of CH
3
OH=
4.097
1.875
×100
=45.8% (From 1 & 3)
Mole % of H
2
O=
4.097
2.222
×100
=54.23% (from 2,3)
Hence, the correct option is A
Answer:
54.23%
Explanation:
Given,
60% by mass solution of CH
3
OH. That means in 100gm solution
60gm CH
3
OH is dissolved in 40gm H
2
O
∴ Molar mass of CH
3
OH=32g/mol
Molar mass of H
2
O=18g/mol
⇒ No. of moles of CH
3
OH=
32g/mol
60gm
=1.875 mol ..........(1)
No. of moles of H
2
O=
18gm/mol
40gm
=2.222 mol ..........(2)
Total no. of moles=1.875+2.222=4.097 moles ..........(3)
⇒ Mole percentage=
Total no. of moles
Moles of compound
×100
Mole % of CH
3
OH=
4.097
1.875
×100
=45.8% (From 1 & 3)
Mole % of H
2
O=
4.097
2.222
×100
=54.23% (from 2,3)