Question

Calculate the molecular formula of a compound with the following percentage by composition sodium 16.1%, carbon 4.2%, oxygen 16.8, water of crystallization 62.9%

Answer 1

Answer:

Relative atomic masses: Na = 23.0, C = 12.0, O = 16.0

Relative molecular mass of H₂O = 18.0

In the compound, mole ratio Na : C : O : H₂O

= (16.1/23.0) : (4.2/12.0) : (16.8/16.0) : (62.9/18.0)

= 0.696 : 0.35 : 1.05 : 3.49

= (0.696/0.35) : (0.35/0.35) : (1.05/0.35) : (3.49/0.35) … Divided by the smallest number

= 2 : 1 : 3 : 10