Question

calculate the molecular mass and find iut the percentage composition of the water of crystallization of ZnSO4 . 7 H2O if zn = 65.5u, S = 32 and O = 16​

Answer 1

Molecular weight of white vitriol ZnSO4 .7H2

O=65+32+(4×16)+7(2×1+16)=287 g

Weight of Zn in white vitriol = 65 g

Percentage weight of Zn =

Molecularweightofwhitevitriol

WeightofZn ×100= 28765×100=22.65 %

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