calculate the molecular mass and find iut the percentage composition of the water of crystallization of ZnSO4 . 7 H2O if zn = 65.5u, S = 32 and O = 16
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Molecular weight of white vitriol ZnSO4 .7H2
O=65+32+(4×16)+7(2×1+16)=287 g
Weight of Zn in white vitriol = 65 g
Percentage weight of Zn =
Molecularweightofwhitevitriol
WeightofZn ×100= 28765×100=22.65 %
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