Calculate the molecular mass of acetic acid and glucose
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Explanation:
formula of acetic acid
CH₃COOH
formula of glucose
C₆H₁₂O₆
molecular mass of acetic acid
= 6×1+1×3+6×1+8×1+8×1+1×1
= 12+3+12+32+1
= 15+44+1
= 15+45
= 60g (60u)
molecular mass of glucose
= 6×6+1×12+8×6
=36+12+48
=48+48
=96g (96u)
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