Calculate the molecular mass of glucose (C6H12O6) molecule in amu
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Answered by
2
Answer:
180amu
Explanation:
12×6+12×1+16×6=180 amu
Answered by
1
Answer:
The molecular mass of glucose (C6H12O6) molecule in amu = 180.156 g/mol
Explanation:
C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g.
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