Question

Calculate the molecular mass of glucose (C6H12O6) molecule in amu​

Answer 1

Answer:

180amu

Explanation:

12×6+12×1+16×6=180 amu

Answer 2

Answer:

The molecular mass of glucose (C6H12O6) molecule in amu = 180.156 g/mol

Explanation:

C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g.