Calculate the molecular mass of the following:
a) CuSO4.5H2O
b) (NH4)2CO3
c) (NH2)2CO
d) Mg3N2
Given atomic mass of Cu = 63.5; H = 1; O = 16; C = 12; N = 14; Mg = 24; S = 32
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Answer:
1 ) Cuso4.5h20
(63.5)+(32)+(16)(4)+5(18)
63.5 + 32 + 64 + 90 = 249.5 amu
2) (NH4)2CO3
(14 + 4)(2) + 12 + (16)(3)
36 + 12 + 48 = 96 amu
3 ) (NH2)2 CO
(14 + 2 ) (2) + 12 + 16
36 + 12 + 16
64 amu
4 ) mg3 n2
24× 3 + 14 × 2
72 + 28
100 amu
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