Question

Calculate the molecular mass of the following

(a) NH4NO3 (b) HNO3 (Given, atomic masses N =14 u. O = 16 u. H =l u)​

Answer 1

Answer:

a) 80u b) 63u

Explanation:

Nitrogen in NH4NO3 is=14 ×1=14

hydrogen=1×4=4

Nitrogen =14×1=14

oxygen = 16×3=48

by adding 14+4+14+48 we get 80 u

hydrogen in HNO3 is =1×1=1

nitrogen=14×1=14

oxgen=16×3=48

by adding we get 1+14+48=63u