calculate the molecular mass of the following components-Na2B4O, 10 H2O
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"Answer: Sodium tetraborate with 10 bounded water molecules has the Molecular mass = 382 amu
Explanation:
Na2B4O = 23 x 2 + 11 x 4 + 16 x 7 + 10(16+1x2)= 46 + 44 + 112 + 180 = 382 "
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