Calculate the molecular mass of the following compounds. ( C=12 , C1=35.5 . O=16 , H=1, k=39, Na=23,N=14 ) 1) sodium carbonate (Na Co3) 2) Carbon tetrachloride (CC14 ) 3) potassium Nitrate (KNO3)
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1
Answer:
Explanation:
CO2 ⇒ 1 × 12 + 2 × 16 = 12 +32 = 44 u
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Answer:
sodium carbonate (Na Co3)=106g /mole
Carbon tetrachloride (CC14 )=154g/mole
potassium Nitrate (KNO3)=101 g /mole
Explanation:
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