Calculate the molecular masses of the following compounds (a) Methanol, CH3OH
(b) Ethanol, C2H5OH
Answers
Answer: in reality
Methanol (CH3OH) = 32.04 g mol−1
Ethanol (C2H5OH) = 46.07 g/mol
Explanation:
But if you calculate it by formula
C=12, H=1, O=16
Methanol (CH3OH) =
[ {1×(12)} + {3×(1)} + {1×(16)} + {1×(1)} ] = 32
Ethanol (C2H5OH) =
[ {2×(12)} + {5×(1)} + {1×(16)} + {1×(1)} ]
=46
The molecular masses of methanol (CH3OH) is 32u and that of ethanol (C2H5OH) is 46u.
Explanation:
In any compound, the sum of atomic masses of all the elements is called the molecular mass.
(i) The Molecular mass of methanol (CH3OH)
= Mass of C + Mass of 3 H atoms x Hydrogen’s atomic mass + Atomic mass of O + Mass of H
= 12 + 1 (3) + 16 + 1 = 32 u
(ii) The Molecular mass of ethanol (C2H5OH)
= Mass of C + Mass of 5 H atoms x Hydrogen’s atomic mass + Atomic mass of O + Mass of H
= 12X2+1X5+16+1=46u
You can get all the answers of Chapter 3 in the link below:
https://brainly.in/question/15041870
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