calculate the molecular weight of a gas x which diffuses four times as another gas Y. which in turn diffuses twice as fast as another gas Z molecular weight of Z is 128
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By graham's diffusion law
r₁=diffusion rate of X
r₂=diffusion rate of Y
r₃=diffusion rate of Z
r₁/r₂= √molecular mass of Y/√molecular mass of X.....eq. (1) {diffusion rate is inversely proportional to the root of molecular mass of gas}
& r₁=4r₂
r₂/r₃=√molecular mass of Z/√molecular mass of Y....eq. (2)
r₂=2r₃ so by putting this in eq. (2) we get molecular mass of Y= 32
and by putting the molecular mass of Y in eq. (1) we get
molecular mass of X=2
hope it helps!
r₁=diffusion rate of X
r₂=diffusion rate of Y
r₃=diffusion rate of Z
r₁/r₂= √molecular mass of Y/√molecular mass of X.....eq. (1) {diffusion rate is inversely proportional to the root of molecular mass of gas}
& r₁=4r₂
r₂/r₃=√molecular mass of Z/√molecular mass of Y....eq. (2)
r₂=2r₃ so by putting this in eq. (2) we get molecular mass of Y= 32
and by putting the molecular mass of Y in eq. (1) we get
molecular mass of X=2
hope it helps!
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Explanation:
the answer of the qution is x=2
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