Question

calculate the molecular weight of a gas x which diffuses four times as another gas Y. which in turn diffuses twice as fast as another gas Z molecular weight of Z is 128

Answer 1

By graham's diffusion law 
r₁=diffusion rate of X
r₂=diffusion rate of Y
r₃=diffusion rate of Z

r₁/r₂= √molecular mass of Y/√molecular mass of X.....eq. (1) {diffusion rate is inversely proportional to the root of molecular mass of gas}

& r₁=4r₂

r₂/r₃=√molecular mass of Z/√molecular mass of Y....eq. (2) 

r₂=2r₃ so by putting this in eq. (2) we get molecular mass of Y= 32 

and by putting the molecular mass of Y in eq. (1) we get 

molecular mass of X=2

hope it helps!

Answer 2

Explanation:

the answer of the qution is x=2