Question

calculate the molecular weight of the compound Al(NO3)3 when al=27,n=14,o=16​

Answer 1

Heya user ! ️✋

✍Here's the required answer :

⚫The molecular weight is the sum of weight of all the molecules in the compound.

⚫molecular weight of Al(NO3)3 = 27+ 3(14+16*3)

Al(NO3)3 = 27+ 3(14+16*3)which is equal to : 27+3(14+48)= 27+ 3* 62 = 27+ 186= 213 .

*[ The words in bold and italics are keywords ]

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Thanks for the question ☺

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Answer 2

Answer:

213 g / mol

Explanation:

Given :

Compound Al ( NO₃ )₃

We have to find molecular weight of above compound :

Atomic mass also given :

Al = 27

N = 14

O = 16

Now :

Molecular weight = 27 + ( 14 + 16 × 3 ) × 3

= > 27 + ( 14 + 48 ) × 3

= > 27 + ( 62 ) × 3

= > 27 + 186

= > 213 g / mol

Hence we get required answer!