Calculate the moles of pure KCLO3 present in X g of a sample of impure KCLO3 which on strong heating yeilds y mL of O2 at STP.
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Given : pure KClO3 present in X g of a sample of impure KClO3 which on strong heating gives y ml of O2 at STP.
To find : The number of moles of KClO3 present in X g of the sample of impure KClO3.
solution : here reaction is given ..
2KClO3 ⇔2KCl + 3O2
two moles of KClO3 form 3 moles of oxygen gas.
so, two moles of KClO3 form 3 × 22400 ml of oxygen gas at STP.
⇒y ml of oxygen gas is produced to heat 2y/(3 × 22400) mol of KClO3.
a/c to question,
y ml of O2 gas is produced to heat X g of impure KClO3 sample.
means, X g of impure KClO3 sample contains 2y/(3 × 22400) mol of KClO3.
so, the number of moles of pure KClO3 is 2y/(3 × 22400) = y/(33600) moles
Therefore option (1) is correct choice.
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