Calculate the moles of the substances
a.3.43g of Carbon
b.7.05 of Br2
c.76 g C4H10
d.35.4g of Li2CO3
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Answered by
22
To determine the number of moles, find the molar mass of the substance and divide the given mass by the molar mass.
a. given mass, m = 3.43g
molar mass of carbon, M = 12g
Number of moles, n = 3.43/12 = 0.2858 moles
b. given mass, m = 7.05 g
molar mass of Br₂, M = 139.8g
Number of moles, n = 7.05/139.8 = 0.0504 moles
c. given mass, m = 76g
molar mass of C₄H₁₀, M = 58g
Number of moles, n = 76/58 = 1.3103 moles
d. given mass, m = 35.4g
molar mass of Li₂CO₃ = 74g
Number of moles, n = 35.4/74 = 0.4784 moles
a. given mass, m = 3.43g
molar mass of carbon, M = 12g
Number of moles, n = 3.43/12 = 0.2858 moles
b. given mass, m = 7.05 g
molar mass of Br₂, M = 139.8g
Number of moles, n = 7.05/139.8 = 0.0504 moles
c. given mass, m = 76g
molar mass of C₄H₁₀, M = 58g
Number of moles, n = 76/58 = 1.3103 moles
d. given mass, m = 35.4g
molar mass of Li₂CO₃ = 74g
Number of moles, n = 35.4/74 = 0.4784 moles
shruthi2000:
Thanks a lot!!
Answered by
11
One mole of a substance = Gram Molecular Weight of that substance(GMW)
a. 1 mole of Carbon = GMW of Carbon = 12g
12g of carbon makes 1 mole
3.43g of carbon makes how many moles?
= 1 × 3.43 / 12
= 0.2858 moles ≈ 0.29 moles ≈ 0.3 moles
b. 1 mole of Br₂ = 160g (Br + Br = 80g + 80g)
160g of Br₂ makes 1 mole
7.05g of Br₂ makes how many moles?
= 7.05 × 1 / 160
= 0.044 moles ≈ 0.4 moles
c. 1 mole of C₄H₁₀ = 4(12) + 1(10) = 58g
58g of C₄H₁₀ makes 1 mole
76g of C₄H₁₀ makes how many moles?
= 76 × 1 / 58
= 1.310 moles ≈ 1.3 moles
d.1 mole of Li₂CO₃ = 2(7) + 12 + 3(48) = 74g
74g of Li₂CO₃ makes 1 mole
35.4g of Li₂CO₃ makes how many moles?
= 35.4 × 1 / 74
= 0.478 moles ≈ 0.48 moles ≈ 0.5 moles
a. 1 mole of Carbon = GMW of Carbon = 12g
12g of carbon makes 1 mole
3.43g of carbon makes how many moles?
= 1 × 3.43 / 12
= 0.2858 moles ≈ 0.29 moles ≈ 0.3 moles
b. 1 mole of Br₂ = 160g (Br + Br = 80g + 80g)
160g of Br₂ makes 1 mole
7.05g of Br₂ makes how many moles?
= 7.05 × 1 / 160
= 0.044 moles ≈ 0.4 moles
c. 1 mole of C₄H₁₀ = 4(12) + 1(10) = 58g
58g of C₄H₁₀ makes 1 mole
76g of C₄H₁₀ makes how many moles?
= 76 × 1 / 58
= 1.310 moles ≈ 1.3 moles
d.1 mole of Li₂CO₃ = 2(7) + 12 + 3(48) = 74g
74g of Li₂CO₃ makes 1 mole
35.4g of Li₂CO₃ makes how many moles?
= 35.4 × 1 / 74
= 0.478 moles ≈ 0.48 moles ≈ 0.5 moles
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