Question

calculate the molicules masses of c2h6 ,ch3oh, na2o ,s8,hno3​

Answer 1

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1) C2H6 [ Ethane ]

C = 12

H = 1

====> (2×12) + (1×6)

====> 24 + 6 = 30μ

2) Ch3OH [ Methyl alcohol ]

C = 12

H = 1

O = 16

====> 12 + (1×3) + 16 + 1

====> 12 + 3 + 16 + 1 = 32μ

3) Na2O [ Sodium oxide ]

Na = 23

O = 16

====> (2×23) + 16

====> 46 + 16 = 62μ

4)S8 [ sulfur]

S = 32

====> (8×32) = 256μ

5) HNO3 [ Nitric acid ]

H = 1

N = 14

O = 16

====> 1 + 14 + (16×3)

====> 1 + 14 + 48 = 43μ