Question

calculate the moment of inertia of a cylinder of length 1.5 m,radius 0.05 m and density 8×10000 kg/m about the axis of the cylinder​

Answer 1

Answer:

I=183.36kgm²

Explanation:

volume of cylinder=πr²h

putting length 1.5m as h and radius r 0.05m

V=π0.05²*1.5

V=0.012m³

since density=mass/volume

therefore

8×10⁴×0.012=mass(m)

m=960kg

I=m(l²/12+r²/4)

I=960(1.5²/12+0.05²/4)

l=960(0.19+0.001)

l=183.36kgm²

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