calculate the moment of inertia of a ring of mass 2 kg and radius 2cm about an Axis passing through its centre and perpendicular to its surface
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If AOR is passing through centre and perpendicular to the ring the MOI will be = MR^2
GIVEN = Mass 2kg
Radius = 2 cm =0.02m
So
2×(0.02) ^2
2×0.0004
0.0008 kgm^2
GIVEN = Mass 2kg
Radius = 2 cm =0.02m
So
2×(0.02) ^2
2×0.0004
0.0008 kgm^2
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