Question

Calculate the moment of inertia of a uniform circular disc of mass 400g and radius 10 cm about
(a) diameter of the disc
(B) the axis , tangent to the
dist and parallel to its diameter (c) the axis through the centre of disc and perpendicular to its
plane
​

Answer 1

Answer:

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Explanation:

1. Given Data: M = 500 g = 0.5 kg. R = 10 cm = 10 × 10-2 m Moment of inertia of disc about diameter = Id = 1414 MR2 Id =1414 × 0.5 × 0.1 kg m2 = 0.0125 kg m2

2. Apply a parallel axes theorem, moment of inertia of the disc about a tangent to the disc and parallel to the diameter of the disc = 1414 MR2 + MR2 = 5454 MR2 = × 0.5 × 1 = 0.0625 kgm2

3. Moment of inertia of the disc about an axis passing through the centre of disc and perpendicular to the plane of the disc = 1212 MR2 = 1212 × 0.5 × 0.1

= 0.025 kgm2

Answer 2

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Given Data: M = 500 g = 0.5 kg. R = 10 cm = 10 × 10-2 m Moment of inertia of disc about diameter = Id = 1414 MR2 Id =1414 × 0.5 × 0.1 kg m2 = 0.0125 kg m2 2. Apply a parallel axes theorem, moment of inertia of the disc about a tangent to the disc and parallel to the diameter of the disc = 1414 MR2 + MR2 = 5454 MR2 = × 0.5 × 1 = 0.0625 kgm2 3. Moment of inertia of the disc about an axis passing through the centre of disc and perpendicular to the plane of the disc = 1212 MR2 = 1212 × 0.5 × 0.1 = 0.025 kgm2.

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