Question

calculate the moment of inertia of the earth about its diameter taking it to be a sphere of 10^25 kg and diameter 12,800 km​

Answer 1

Dear Student,

● Answer -

Moment of inertia = 1.638×10^38 kgm²

◆ Explanation -

# Given -

M = 10^25 kg

D = 12,800 km

# Solution -

Radius of earth is -

R = D/2

R = 12800/2

R = 6400 km

R = 6.4×10^6 m

As earth is a solid sphere, its moment of inertia about axis is given by formula -

I = 2MR²/5

Substitute values,

I = 2 × 10^25 × (6.4×10^6)² / 5

I = 1.638×10^38 kgm²

Therefore, moment of inertia of the earth about its diameter is 1.638×10^38 kgm².

Best luck dear...

Answer 2

Answer:

Explanation:

# Given -

M = 10^25 kg

D = 12,800 km

# Solution -

Radius of earth is -

R = D/2

R = 12800/2

R = 6400 km

R = 6.4×10^6 m

As earth is a solid sphere, its moment of inertia about axis is given by formula -

I = 2MR²/5

Substitute values,

I = 2 × 10^25 × (6.4×10^6)² / 5

I = 1.638×10^38 kgm²

Therefore, moment of inertia of the earth about its diameter is 1.638×10^38 kgm².