Question

Calculate the moment of inertia when a magnet of dimensions 3cm X 1cm, where mass of a magnet .018 kg.

Answer 1

Answer:

Correct option is

A

4×10

4

Am

−1

Intensity of magnetisation,

I

m

=

V

M

=

(15×2×1)10

−6

1.2

=4×10

4

Am

−1

Answer 2

Answer:

The moment of inertia is $0.000162 kg m^2$

Explanation:

A specific quantity that is responsible for producing the torque in a body about a rotational axis is called the moment of inertia

First Moment Of Inertia:

“It represents the spatial distribution of the given shape in relation to its relative axis”

Second Moment Of Inertia:

“This specific property displays the point distribution with respect to the axis”

Dimension of magnet =length *breadth =3*1cm

mas of the magnet is =0.18kg

length =3cm

firstly we convert cm to m

3cm =0.03m

Moment of inertia is $ML^2$

$=0.18*(0.03)^2$

$=0.18*0.00009\\=0.000162 kg m^2$