Question

Calculate the moment of resistance of a sold
circular beam section of 120 mm diameter
maximum bending stress is 3.273.68 MPa​

Answer 1

Sunday was bigdkgjrpu47p

Answer 2

Answer:

555.4 Newton meter

Explanation:

Given:- Diameter of circular beam section = 120 mm.

             Maximum bending stress = 3.27368 Mpa.

To Find:- The moment of resistance.

Solution:-

1 meter = 1000 millimeter.

∴ 120 mm = 120/1000 meters

                = 0.12 meters

1 Megapascal = 1000000 pascal

∴ 3.27368 Mpa = 3273680 pascal

As we know, The moment of resistance of a beam is given by

                               M = σ × Z  , where M = Bending moment,

                                                               σ = Bending stress , and

                                                                Z = Section modulus

We also know that, section modulus of a circular beam is

                                Z = $\frac{\pi }{32}$ d³ , where d = diameter of circular beam.

Now, using the above formulas, we can write that

M = σ × $\frac{\pi }{32}$ d³

Substituting the values σ = 3273680 and d = 0.12 in the above formula, we get

M = 3273680 × $\frac{\pi }{32}$ (0.12)³

   = 3273680 × 0.09818 × 0.001728

   = 555.4 Newton meter.             [ ∵ 1 pascal m² = 1 Newton ]

Therefore, the moment of resistance is 555.4 N-m.

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