Question

Calculate the momentum of a moving particle which has de Broglie's wavelength of 200 pm

Answer 1

Answer:

Momentum=3.313×10^-24kgms-

Explanation:

Here,de-broglie wavelength.

wavelenght=h/mv

200× 10^-12=6.626×10^-34/p[1pm=10^-12m,h=6.626×10^-34]

p=6.626×10-34/200×10^-12

p=6.626×10-34/2×10^-10

p=3.313×10^-34+10

p=3.313×10^-24kgms-

Answer 2

The momentum of a moving particle is $3.312\times 10^{-24}kg.m/s$

Explanation:

To calculate the momentum, we use the equation given by De-Broglie's wavelength, which is:

$\lambda=\frac{h}{p}$

where,

$\lambda$ = De-Broglie's wavelength = 200 pm = $2.00\times 10^{-10}m$    (Conversion factor:  $1m=10^{12}pm$  )

h = Planck's constant = $6.624\times 10^{-34}Js$

p = momentum of the particle = ?

Putting values in above equation, we get:

$2.00\times 10^{-10}m=\frac{6.624\times 10^{-34}Js}{p}\\\\p=\frac{6.624\times 10^{-34}Js}{2.00\times 10^{-10}m}=3.312\times 10^{-24}kg.m/s$

Learn more about De-Broglie's wavelength:

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